正則表達式查找和替換 url 不起作用或如何使其起作用 (Regex to Find and Replace url does not work or how to make it work)

問題描述

正則表達式查找和替換 url 不起作用或如何使其起作用 (Regex to Find and Replace url does not work or how to make it work)

Using Regex Hero here are the inputs:

Regular Expression: /category/*

Replacement String: /experiment/$0

Target String: http://google.co.in/blah_blah_blah/domainname.com/category/wp/

Final String:http://google.co.in/blah_blah_blah/domainname.com/experiment//category/wp/

Expected Url

http://google.co.in/blah_blah_blah/domainname.com/experiment/wp/

How do i get the expected URL , is there something wrong in my regex?

‑‑‑‑‑

參考解法

方法 1:

try regex: 

/category/(.*)

In regex . is the wildcard and * is a "0 or more" qualifier. Therefore, Matching 0 or more (*) characters (.) after the forward slash should be expressed as .*

replacement: 

/experiment/$1

$0 is a "pseudo group" that holds the entire match, i.e. "/category/...". You need to use parentheses to define other groups so that you can reference these groups in the replacement pattern, hence the (.*) part in the regex.

方法 2:

You need to change the regex:

/category/([^/]+)

That will match everything up to the next slash. Notice I have also wrapped it in parentheses to capture it. Alternatively, if you just want EVERYTHING after /category/ use:

/category/(.*)

You then need to change your replacement to:

/experiment/$1

$1 is the first match.

this results in:

http://google.co.in/blah_blah_blah/domainname.com/experiment/wp/

(by Deeptechtons、Pencho Ilchev、LeonardChallis)

參考文件

1. Regex to Find and Replace url does not work or how to make it work (CC BY‑SA 3.0/4.0)