Concourse 流水線：如何讓嵌入式腳本使流水線失敗 (Concourse Pipeline: How to have an Embedded Script Fail the Pipeline)

問題描述

Concourse 流水線：如何讓嵌入式腳本使流水線失敗 (Concourse Pipeline: How to have an Embedded Script Fail the Pipeline)

當我在運行參數中運行帶有嵌套 Python 腳本的 Concourse 管道時，如下所示：

‑ task: some‑task
    params:
      ...
    config:
      platform: linux
      ...
      run:
        path: bash
        args:
        ‑ "‑c"
        ‑ |

          python my_failing_python_code.py

當 python 腳本失敗時，拋出退出 1，錯誤似乎不會冒泡我期望的管道。總體而言，管道“成功”結束。

我應該如何設置管道以讀取管道內運行的腳本的退出狀態？

謝謝

參考解法

方法 1:

If that is the whole content of the script, then you can replace it with

run:
        path: python
        args:
        ‑ my_failing_python_code.py

See https://concourse‑ci.org/hello‑world‑example.html

if the shell script does also other things, you are missing a set ‑e, to tell the shell to report an error:

    run:
        path: bash
        args:
        ‑ "‑c"
        ‑ |
          set ‑e
          python my_failing_python_code.py

See https://concourse‑ci.org/tasks.html

(by Austin L、marco.m)

參考文件

1. Concourse Pipeline: How to have an Embedded Script Fail the Pipeline (CC BY‑SA 2.5/3.0/4.0)